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Richard Careaga's avatar

The problem is really very simple.

To start, you, as the contestant, have a one in three chance of having the winning door, and the other two doors, between them, have a joint chance of two in three of having the winning door.

Monty reveals one of the other two doors, showing that it is not the winning door.

Nothing has changed except your information about the other two doors. They still have between them a two in three chance, and it was always evenly split between them, and the only unknown was that IF the winning prize was in one of them, we didn't know which one. Now we do. The un-opened door has the two in three chance and the open door has zero.

You still have the one in three chance, because the new information about the open door tells you nothing about your door. If, by mistake, Monty had opened the winning door, the only new information would be that both your door and the unopened door had zero in three chances. So, there would be no reason to switch. But since he didn't we can trade, with advantage, our one in three for the joint probability of two in three and zero in three.

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